Question

medal!!

Answer 1

ya...

Answer 2

What are the solutions of 3x2 + 6x + 6 = 0?

-2 ± i
-2 ± 2i
-1 ± i
1 ± i

Answer 3

Factor out 3 and divide both sides by that term to get..

x² + 2x + 2 = 0

Then, by standard form..

ax² + bx + c = 0

a = 1
b = 2
c = 2

So by quad. formula..

x = (-b ± √(b² - 4ac))/2a
= (-6 ± √(6² - 4(3)(6)))/6
= (-6 ± √(36 - 72))/6
= (-6 ± √-36)/6
= (-6 ± 6i)/6
= -1 ± i

I hope this helps!

Answer 4

thank you!!!