Solve, using the substitution method.
y – 2x = 8
16 + 4x = 2y
A.
The only solution is (24, 0).
B.
There are an infinite number of solutions.
C.
The only solution is (1, 10).
D.
There is no solution.
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jimthompson5910 (jim_thompson5910):
Start with y - 2x = 8
jimthompson5910 (jim_thompson5910):
do you see how you would isolate y in y - 2x = 8 ?
OpenStudy (anonymous):
yah, so it would be: y=2x+8? @jim_thompson5910
jimthompson5910 (jim_thompson5910):
correct
jimthompson5910 (jim_thompson5910):
once you know that y = 2x+8, you can replace every copy of y in the second equation with 2x+8
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jimthompson5910 (jim_thompson5910):
16 + 4x = 2y
16 + 4x = 2( y )
16 + 4x = 2( 2x+8 ) ... replace every copy of y with 2x+8
now solve for x
OpenStudy (anonymous):
k so now you need to distribute it, so 2*2x=4x and 2*8= 16 right?
jimthompson5910 (jim_thompson5910):
yes
OpenStudy (anonymous):
so 16 + 4x = 4x + 8 now we need to isolate the x
jimthompson5910 (jim_thompson5910):
yes
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OpenStudy (anonymous):
wait so now it would be 16 + 4x - 8/4 = x
i think i did it wrong..
OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
not sure how you're getting that
jimthompson5910 (jim_thompson5910):
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jimthompson5910 (jim_thompson5910):
|dw:1418949600013:dw|
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jimthompson5910 (jim_thompson5910):
oh btw, I just noticed this, but you distributed incorrectly
jimthompson5910 (jim_thompson5910):
2( 2x+8 ) should be 4x + 16
OpenStudy (anonymous):
oh yah, i guess i forgot to multiply the 2*8
jimthompson5910 (jim_thompson5910):
so you really have
16 + 4x = 4x + 16
jimthompson5910 (jim_thompson5910):
If you rearrange terms, you go from
16 + 4x = 4x + 16
to
4x + 16 = 4x + 16
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jimthompson5910 (jim_thompson5910):
and we have something in the form x = x, which is ALWAYS true for any real number x