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PLEASE HELP ME (Algebra 2 material)
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\[f(x)=ax^2+bx+c\] \[f(0)=0+0+c=5\] and you got \(c=5\) to begin with then it is harder
\[f(x)=ax^2+bx+5\\ f(-2)=4a-2b+5=1\]\[4a-2b=-4\] is one equation try this again with \(f(4)\) to get another equation in \(a\) and\(b\)
ohhh okay thank you. :)
@misty1212 my final answer was y= -3x^2 - 4x + 5 is that right?
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