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The product of (n2 – 6n + 3) and -4n is
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is the first term n2 or n^2?
Hello @code97man and Welcome to OpenStudy! :) you are currently in the Chemistry group you will receive a better and faster answer if you would post this question in the Mathematics group :) you would use distributive property for this problem (-4n)*(n^2 - 6n + 3) would become (-4n)*(n^2) + (-4n)*(6n) + (-4n)*(3) can you simplify that? :)
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