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Solve: |y + 8| ≥ 3
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subtract 8 from both sides. y is greater than or equal to -5
\[\left| x+a \right|\ge b,x+a \le -b~and~x+a \ge b\]
You break it into two equations. \(y + 8 \ge 3\) and \(-y - 8 \ge 3\)
Can you solve both of those? @RainbowsxD
\[y+8\ge 3\] or \(y+8\leq -3\)
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Misty, the 3 wasn't in absolute value symbols so it wouldn't be 3 or -3. it would be -y - 8 or y + 8.
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