Question

what are the real and complex solution of the polynomial equation x^3-64=0

Answer 1

factor this one using the difference of two cubes
\[a^3-b^3=(a-b)(a^2+ab+b^2)\]

Answer 2

here you have \(x^3-64\) the same as
\[x^3-4^3\] factors
\[(x-4)(x^2+4x+16)\]

Answer 3

\[x-4=0\\
x=4\] the other two you need to use the quadratic formula or complete the square for \[x^2+4x+16=0\]

Answer 4

misty1212 would it be \[-2+2i \sqrt{3},-2-2i \sqrt{3}\]