Question

Check all that apply. More than one answer.
sec 2x=
A. 1/cos^2x - sin^2x
B. 1/sin^2x - cos^2x
C. 1/2sin^2x - 1
D. 1/1-2sin^2x

Answer 1

abc or d

Answer 2

ya it could be one of those

Answer 3

sorry don't know

Answer 4

thats alright :)

Answer 5

a_d

Answer 6

a and d I think

Answer 7

how did you get a and d M A?

Answer 8

secx=1/cosx
sec2x=1/cos2x
cos2x= cos^2-sin^2
cos2x=1-2sin^2

Answer 9

ah ok :) Thank you!!!

Answer 10

yourwelcome

Answer 11

:D

Answer 12

;)