Question

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Answer 1

hey whats the original question ?

Answer 2

one sec

Answer 3

Oh you're changing dydx to dxdy

Answer 4

it doesn't look correct

Answer 5

lets sketch the region quick

Answer 6

\[\int\limits_{0}^{1}\color{red}{\int\limits_{0}^{2x}}f(x; y)dydx + \int\limits_{1}^{2}\color{red}{\int\limits_{0}^{2x(2-x)}}f(x; y)dydx\]

between x=0 and x=1, y is ranging from 0 to 2x :

Answer 7

between x=1 and x=2, y is ranging from 0-> 2x(2-x) :