What is the equation of y equals x cubed with the given transformations? vertical stretch by a factor of 3, horizontal shift 4 units to the right, vertical shift 3 units down
Horizontal shift of f(x) ---> f(x + a) Vertical shif f(x) ----f(x) +a
stretch f(x) --->a*f(x)
Use f(x) = x^3 with those transformations
Horizontal stretch: \(\displaystyle y=f(\frac{x}{k})\) Vertical stretch: \(y=kf(x)\) Horizontal shift: \(y=f(x-k)\) Vertical shift: \(y=f(x)+k\) By the magnitude of \(k\).
So I have y=3(x^3-4)+3?
Nope, perform the steps one by one
it should be (x-4)^3 instead of x^3-4, for that matter
Okay so to start I do the vertical stretch by 3 y=3 (x^3) Then the horizontal y=3(x-4)^3 Then the vertical shift y=3(x-4)^3-3 Like this?
Yep, exactly.
Thanks!
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