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@DanJS
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Same as the others, separate the variables and integrate...
\[\int\limits \frac{ 1 }{ 4y }*dy = \int\limits \frac{ 1 }{ x^2 }*dx\]
Think you forgot one thing...
solving that i got ....
\[y = C*e ^{-4/x} \]
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\[\frac{ 1 }{ 4 }*\ln(y) = \frac{ -1 }{ x } +C\]
i know what i did, youre right
i made a mistake
thank you (: i only have one more question left hahaha
\[\ln(y) = \frac{ -4 }{ x } + C\]
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4C = C ---arbitrary constant
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