Question

the perimeter of a rectangle is twice the sum of its length and its width. the perimeter is 22 meters and its length is 2 meters more than twice its width. what is its length?
HELP

Answer 1

\(2(l+w)=22\\l=2w+2\\\)

Answer 2

P=2(l+w)

Solve for l
22=2((2+2w)+w
4+4w+w=22
4+5w=22
22-4=18
18/5=3.6
l=3.6

Answer 3

And, to check that:

Solve for w
22=2(3.6+w)
22=7.2+2w
22-7.2=14.8
14.8/2=7.4
w=7.4

Check
22=2(3.6+7.4)
22+2(11)
22=22