Mathematics
20 Online
OpenStudy (anonymous):
The sum of the angle measures of a polygon with s sides is 2,340o. Find s
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OpenStudy (anonymous):
@AlexandervonHumboldt2
OpenStudy (alexandervonhumboldt2):
180*(n-2)=2340
OpenStudy (alexandervonhumboldt2):
180*(s-2)=2340
OpenStudy (alexandervonhumboldt2):
15
OpenStudy (alexandervonhumboldt2):
@bohotness
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OpenStudy (anonymous):
@AlexandervonHumboldt2
did i do this right?
OpenStudy (alexandervonhumboldt2):
15 should be
OpenStudy (alexandervonhumboldt2):
sum of inteior anles of poly is 180*(n-2)
OpenStudy (cwrw238):
yes 15 is correct
OpenStudy (xapproachesinfinity):
seems good to me
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OpenStudy (cwrw238):
one other bit of knowledge which might be useful sometimes is the sum of the exterior angles of ALL polygons is 360 degrees
OpenStudy (anonymous):
180-124=y
x+y+125+65=360
y=54 x=114
OpenStudy (anonymous):
did i do this right?
OpenStudy (anonymous):
@AlexandervonHumboldt2
OpenStudy (anonymous):
@xapproachesinfinity @cwrw238
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OpenStudy (cwrw238):
No angle y = 180 - 116 = 64
OpenStudy (cwrw238):
and angle x = 360 - (64+72+65)
OpenStudy (cwrw238):
sorry that's 125 not 65
OpenStudy (anonymous):
then solve for x?
OpenStudy (cwrw238):
yes
x = 360 - (125+72 + 65)
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OpenStudy (cwrw238):
the 4 angles of a quadrilateral add up to 360 degrees.
OpenStudy (cwrw238):
well you can work that out i'm sure
add 125+64+72 using your calculator
the subtract that from 360
OpenStudy (anonymous):
x=360 - (262) ? @cwrw238
OpenStudy (anonymous):
sooo 98
OpenStudy (cwrw238):
360 - 261
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OpenStudy (cwrw238):
99
OpenStudy (cwrw238):
oh - my error - i wrote 65 instead of 64
360 - (125+72+64) = 360 - 261 = 99
OpenStudy (cwrw238):
i think im a little tired ...
OpenStudy (anonymous):
y=180 - 116 =64
x=360 - (54+72+125)
x=360-261
x=99
OpenStudy (anonymous):
@cwrw238 @AlexandervonHumboldt2