Question

simplify the cube root of 32x^6 y^4

Answer 1

are you rewriting my question?

Answer 2

you wrote my question wrong

Answer 3

its 32x but its ok go on

Answer 4

\[\sqrt[3]{32 x^6y^4}=\left( 32 x^6 y^4 \right)^{\frac{ 1 }{ 3 }}=\left( 2^3*4\left( x^2 \right) ^3y^3y \right)^{\frac{ 1 }{ 3 }}\]
=?

Answer 5

Already figured this out a more easier way. Thanks for the help though.