Question

What is the equation of the line passing through (-7,4) whose intercepts are numerically equal but of opposite signs?

Answer 1

Need help?

Answer 2

Yeah

Answer 3

for this im going to assume you know qudratics

y-int = -x
x-int = x
so we have the points (x,0), (-x,0), (-7,4)

so we have gradients of
-(4+x)/7 and -4/(7+x)

as they are the same gradient
-(4+x)/7 = -4/(7+x)
solving for -(4+x)/7 = -4/(7+x)
(x+4)(x+7)=28
x^2+11x+28=28
x^2+11x=0
x(x+11)
x=-11 or x=0
x=0 isn't applicable because of some reason that i dont know

so subbing x=-11 in our first cordinates we get
(-11,0),(0,11),(-7,4)

gradient= (4-11)/(-7-0)
= 1
using one point formula
y-11=x
x-y+11=x or y=x+11

Answer 4

Sorry took a while :( hope it helps!!!:)

Answer 5

It's alright thank you!

Answer 6

I'm glad I helped dear!!! : )