3x + 80 = -2x x =
Subtract.
First, we subtract 80 to both sides: 3x = -2x - 80 Now add 2x to both sides, what do you get?
3x - -2x
Wut?
5?
you mind to start over?
Yea You Can
okay, so your question says: \(\large\color{black}{ 3x + 80 = -2x }\) you want the X-s on the one side, and the number(s) on the other. Subtract 3x from both sides. \(\large\color{black}{ 3x + 80 \color{red}{-3x}= -2x \color{red}{-3x} }\) can you simplify on the left side?? (what cancels ? )
anything that troubles you?
3x+80-3 So I Add And Subtract?
you are subtracting like terms on both sides. when I subtracted 3x from both sides, I got: \(\large\color{black}{ 3x + 80 \color{red}{-3x}= -2x \color{red}{-3x} }\) I will label the like terms on each side: \(\large\color{black}{ \color{blue}{3x}+ 80 \color{blue}{-3x}= \color{green}{-2x} \color{green}{-3x} }\)
what do you get on each of the sides, can you tell me, please?
0 & -5
yes, you get ZERO Xs on the left side. and NEGATIVE FIVE Xs on the right side. this is what we do: \(\large\color{black}{ \color{blue}{3}x+ 80 \color{blue}{-3}x= \color{green}{-2}x \color{green}{-3}x }\) \(\large\color{black}{ \color{blue}{0}x+ 80= \color{green}{-5}x }\)
\(\large\color{black}{ 0x }\) is still \(\large\color{black}{ 0 }\), so you basically got. \(\large\color{black}{ 80= \color{green}{-5}x }\). Can you solve for x?
-16
yes, there you go!
Thank You So Much
This is not a problem!
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