Question

Make tables to find the solution to 2^-x=4^x+3 take the integar values of x only between -3 and 3

Answer 1

Is your question
1.\[2^{-x}=4^x+3\]
or 2. \[2^{-x}=4^{x+3}\]

Answer 2

Number 2.

Answer 3

4 = 2^2

set exponents equal

-x = 2(x+3)

Answer 4

\[2^{-x}=\left( 2^2 \right)^{x+3}\]

Answer 5

I don't understand how to solve it

Answer 6

@surjithayer are you still there?