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@jojo4eva @iGreen
.the three sides are given equal hence it is equilateral truangle and \(\large\tt \begin{align} \color{black}{2x+5=4x-1 }\end{align}\)
So A ?
Yep, we write: \(2x + 5 = 4x - 1\) Can you solve for 'x'? @keke_luvs_u
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A ?
Tell me how you got A..
lol
4x - 1 = 1
First subtract 5 to both sides.. \(2x + 5 \color{red}{- 5} = 4x - 1 \color{red}{-5}\)
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-.- Then?
Tell me what you get.
Simplify that.
I dont know
10
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@iGreen
Thanks for no help -.-
Um..I have no idea how you got 10 from that.. 5 - 5 = 0 -1 - 5 = 6 \(2x = 4x - 6\) Sibtract 4x to both sides.. what's 2x - 4x?
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