Question

Using a directrix of y = -3 and a focus of (2, 1), what quadratic function is created?

Answer 1

Are you stalking me? This is the same question I have on my test right now. e_e

Answer 2

f(x) = (1/2)(x - 2)^2 + 1

Answer 3

@One098 lol is it OCVS? And no this is a practice question for me lol

Answer 4

Uh no? It's FLVS.

Answer 5

Well FLVS and OCVS are pretty much the same thing...i switched to OCVS because they give diplomas...

Answer 6

Yeah <_< Oh well its my last year there then I'm off to college..

Answer 7

lol ur in 12th? Im doing 10th grade work...

Answer 8

Nope. I'm in 10th.

Answer 9

Dual Enrollment?

Answer 10

I'm in 10th but I did 10th 11th and 12th all in this school year.

Answer 11

._.
well dam.

Answer 12

haha :P

Answer 13

I'm in 10th in FLVS also..lol.

Answer 14

lol do you have an answer to this question by chance?

Answer 15

@Directrix

Answer 16

As a start : find the vertex of parabola

Answer 17

I thought vertex and focus was the same thing lol...

Answer 18

I just found out im wrong /.\

Answer 19

My new answer is:
f(x) = (1/8)(x - 2)^2 - 1

Answer 20

No..they aren't..

Answer 21

thats right! how did you get that ?

Answer 22

The focus is located on the line of symmetry..

Answer 23

I used a graphing calc XD

Answer 24

LOL