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A diver descends below the surface of the water at a rate of 9.3 m/min. What is the diver’s altitude relative to sea level after 3 min?
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given: constant velocity \(v=9.3 \text{m/min}\) time \(t=3min\) distance = steep times time
the altitude relative to sea is simple the distance travelled by the diver from the sea level.
9.3 * 3?
correct.
27.9
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