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Liberal Arts Math
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Du you remember the pythagorean theorem?
Do*
No
|dw:1419348595007:dw| \[(AC)^2 = (AB)^2 + (BC)^2\]\[AC = \sqrt{(AB)^2 + (BC)^2}\]
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Plug in the values for AB and BC and evaluate.
AC = 5^2 + 14.14^2
AC = 25 + 199.9 = 14.9
oh no dear
the square of \(\sqrt{200}\) is \(200\) not \(199.9\)
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and that makes your answer exactly \(15\)
Thank you!
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