Question

What is the solution to the system of equations?
5x-3y=-9
2x-5y=4
will fan and medal

Answer 1

one second

Answer 2

x=-3 y=-2

Answer 3

@Aleah.wood0613 Please do not give answers.

Read the code-of-conduct:

http://openstudy.com/code-of-conduct

Answer 4

my favorite way since algebra 2 class.
\(\large\color{black}{ \left[\begin{matrix}5 & ~~-3&~~-9 \\ 2 & ~~-5&~~4\end{matrix}\right] }\)

Answer 5

\(\large\color{black}{ \left[\begin{matrix}5 & ~~-3&~~~~~-9 \\ 2 & ~~-5&~~~~~~4\end{matrix}\right] }\)


\(\large\color{black}{ \left[\begin{matrix}10 & ~~-6&~~~~~-18 \\ -10 & ~~25&~~~~~~-20\end{matrix}\right] }\)


\(\large\color{black}{ \left[\begin{matrix}10 & ~~-6&~~~~~-18 \\ 0 & ~~19&~~~~~~-38\end{matrix}\right] }\)


\(\large\color{black}{ \left[\begin{matrix}10 & ~~-6&~~~~~-18 \\ 0 & ~~1&~~~~~~-2\end{matrix}\right] }\)

Answer 6

now you need the x....

Answer 7

this is what we do with the first row:

\(\large\color{black}{ \left[\begin{matrix} 0 & ~~1&~~~~~~-2\end{matrix}\right] }\) times 6, >> \(\large\color{black}{ \left[\begin{matrix} 0 & ~~6&~~~~~~-12\end{matrix}\right] }\)

add this to the 1st row:
\(\large\color{black}{~~~ \left[\begin{matrix} 10 & ~~-6&~~~~~-18\end{matrix}\right] }\)
\(\large\color{black}{ ^{^+}\left[\begin{matrix} 0 & ~~~~~~~~~6&~~~~~~-12\end{matrix}\right] }\)
-------------------------------
\(\large\color{black}{ \left[\begin{matrix} 0 & ~~0&~~~~~~-30\end{matrix}\right] }\)

Answer 8

I meant 10, 0 -30 for the very last thing.

Answer 9

So we get;

\(\large\color{black}{ \left[\begin{matrix}10 & ~~0&~~~~~-30\\ 0 & ~~1&~~~~~~-2\end{matrix}\right] }\)

dividing the 1st row by 3,

\(\large\color{black}{ \left[\begin{matrix}1 & ~~0&~~~~~-3\\ 0 & ~~1&~~~~~~-2\end{matrix}\right] }\)

Answer 10

I mean once the answer was given away I went ahead and verified it

Answer 11

thanks for explaining it better

Answer 12

yw, if that expln. is a satisfactory