Question

differentiate y=e^(sinx)/cosx
u=sinx
du/dx=cosx
dy/dx=cosx.e^(sinx)/-sinx
=-e^(sinx)/tanx is this true?

Answer 1

\[y=\frac{ e ^{\sin x} }{ \cos x }\]
\[y=\frac{ u }{ v }=\frac{ v \frac{ du }{ dx }- u \frac{ dv }{ dx }}{ v^2 }\]

Answer 2

thanks

Answer 3

yw