The product of two consecutive integers is 420. An equation is written in standard form to solve for the smaller integer by factoring.

What is the constant of the quadratic expression in this equation?

x2 + x +.... = 0

Question

The product of two consecutive integers is 420. An equation is written in standard form to solve for the smaller integer by factoring.

What is the constant of the quadratic expression in this equation?

x2 + x +....  = 0

anonymous · Answer

@Nnesha @robtobey

hartnn · Answer

2 consecutive integers are x,x+1

their product is 420

hartnn · Answer

x(x+1) =420
try an simplify this...
bring 420 on left side

anonymous · Answer

so 420x(x-1) ?

hartnn · Answer

*sigh*
whats x(x+1)  equal to??
use distributive property...

anonymous · Answer

1

hartnn · Answer

wow
ok, here are the steps, 
go through them and ask doubts :)

$x(x+1) =420 

 \x^2 +x = 420 \ x^2+x-420 = 420-420 \ x^2+x-420 =0$

so your answer is -420

anonymous · Answer

@hartnn Im Not The Best At Math Sorry :(

hartnn · Answer

don't be sorry!
practice and become good at it :D

anonymous · Answer

So The Answer is -420

hartnn · Answer

yes