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Capture 1: find the remaining angle of the triangle, which will be 180-(35+50)= 95degrees Then solve forces vertically and horizontally. R(horizo): instead of FT2 and FT1 I will consider as T2 and T1, respectively. So, we will have T2cos50=T1cos35, then T2=0.78T1 R(verti): T2sin50+T1sin35=64
Replace the T2 you got in the 2nd one and find it as an equation. Then go back to the first equation to find T1. Done. Try to use the same methodology in the picture2.
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