Question

What is the solution set of this system of equations?

y = x2 − 3x − 4
x = y + 8

Answer 1

Flip the first second equation so you have the \(y\)s on the same side.\[
y+8=x
\]

Answer 2

Then you subtract the second one from the first. \[
\underbrace{y}_{-(y+8)} = \underbrace{x^2-3x-4}_{-x}
\]

Answer 3

You will get: \[
-8=x^2-4x-4
\]This is a quadratic equation. Can you solve it now?

Answer 4

yes, thank you