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Silly little problem, solve for x:
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\[\Large 2 \sinh(\ln x)=1\]
If I apply the definition of sinh x, I get:
The answer is kind of a special number
\[x ^{2}-2x-1=0\] the unique acceptable solution is:
\[x=\frac{ 1+\sqrt{5} }{ 2 }\] namely the golden number!!!!!
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oops the equation is: \[x ^{2}-x-1=0\]
This was cute :)
that's true! @iambatman
Haha yep. I sort of accidentally came across this while trying to find an alternate path to solving eliassaab's problem. Alright merry xmas peeps, that's all I've got for today lol.
merry xmas to all!! @Kainui @iambatman
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Haha, Merry Christmas! :P
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