The Royals softball team played 75 games and won 55 of
them. What percent of the games did they lose? (round to
the nearest tenth??

Question

The Royals softball team played 75 games and won 55 of 
them. What percent of the games did they lose? (round to 
the nearest tenth??

compassionate · Answer

Hi,

So they played 75 games (100%) and only won 55. Simply divide 55 into 75. $$\frac{ 75 }{ 55 }$$

michele_laino · Answer

please note that the games lost are 75-55=20, so if we apply the standard definition of probability, namely favorable cases over possible cases, we get?

anonymous · Answer

They played 75 games and only won 55 of them:
55/75
Simplify it to get:
11/15
Its asking you to find the percent of the games they lost so, you subtract 15-11=4
4/15=x/100
Proportion
You'll get 26.7% if you round your answer to the nearest tenth.

mathstudent55 · Answer

They played 75 games and won 55.
The number of games they lost is 75 - 55 = 20
The percentage of games they lost is:
$\dfrac{20}{75} \times 100\% = 26.66666...\%$
Since they ask to round to the nearest tenth, the answer is: 
They lost 26.7% of the games.

triciaal · Answer

@compassionate please read the question before answering. 
in addition, the percentage is usually a fraction  of the whole so will be less than 100 
the whole  = amount loss + amount won

anonymous · Answer

How many ties?

anonymous · Answer

zero ties

anonymous · Answer

20/75*100= 26.7 %

anonymous · Answer

55 divided by 75 that how you get the percentage. Then time the number by one hundred then round up or down.
55 divided by 75 equals 73%