Question

where does the graph y=sinx intersect y=1-cos x. Give the number of intersections between and including 0 and 360

Answer 1

ye

Answer 2

:)

Answer 3

did you try to graph sin x and 1 - cos x

Answer 4

yes but im supposed to name the angles?

Answer 5

we need to find how many times y = sin x and y = 1 - cos x intersect on the interval [0,360]

Answer 6

pretty clear that they intersect at \((0,0)\) right?

Answer 7

To me:
sinx = 1-cosx --> sinx + cos x =1. square both sides to have \(sin^2x +cos^2x +2sinxcosx =1\).--> 2sinx cosx =0 . hence either sinx =0 or cos x =0
If sin x =0, hence x =0 or pi, or 2pi.
If cos x =0, hence x = pi/2, 3pi/2
Those are solutions.

Answer 8

um r u sure because the choices are 0, 1, 2, 3, 4

Answer 9

hehehe.... so?? just convert to the times, right? you have 2 times for sinx =0, and 2 times for cosx =0, that shows it =0 4 times, right?