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Which number in the monomial 125x18y3z25 needs to be changed to make it a perfect cube?
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@Directrix
Look at the components of the term to see which ones are already perfect cubes.
x shoul be in cube
125 = 5 ^3 x^18= ( x^6)^3 y^3 = ? z^25 = ?
@iam.dhue
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3 Is
125 = 5 ^3 x^18= ( x^6)^3 y^3 = (y)^3 z^25 = ?
Now, what about the power of x.
Divide 3 into 25. What do you get?
.12
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I think you did 3 divided by 25.
Do 25 divided by 3. |dw:1419613638935:dw|
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