Mathematics
20 Online
OpenStudy (anonymous):
Helpppppppppppppppppppppppppppp
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OpenStudy (anonymous):
OpenStudy (anonymous):
@MARC_
@TheSmartOne
TheSmartOne (thesmartone):
Do you know what "mean" means?
OpenStudy (anonymous):
yes
TheSmartOne (thesmartone):
we just add up all the x values for all the given points and divide them by how many of them there are.
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OpenStudy (anonymous):
Just add up all the numbers, then divide by how many numbers there are.
TheSmartOne (thesmartone):
So for example if the point is (1,0) and (2,0) we add up 1+2 which equals 3 and then since there are 2 numbers 3/2 is the mean.
TheSmartOne (thesmartone):
Do you get that?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
so 1.5
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TheSmartOne (thesmartone):
I was just giving you an example with random points...
OpenStudy (anonymous):
oh ok I get the example
TheSmartOne (thesmartone):
lol. yeah :P
TheSmartOne (thesmartone):
So what are the points?
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TheSmartOne (thesmartone):
They will be in the form of
(Variable A, Variable B)
TheSmartOne (thesmartone):
Then we will add up all the 8 values for variable A and then divide it by 8 to get the mean.
TheSmartOne (thesmartone):
so what do you get?
OpenStudy (anonymous):
ok so I add got 30 and divide by 8 and got 3.75
TheSmartOne (thesmartone):
there are 8 x values... add tehm all up. you should get a bigger number than 30...
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TheSmartOne (thesmartone):
x values refers to (x,y)
OpenStudy (anonymous):
86/8=10.75
TheSmartOne (thesmartone):
umm..
TheSmartOne (thesmartone):
Lets first put up all the points.
TheSmartOne (thesmartone):
(2,2) , (2, 8) , (4,3) , (5,1) , (6,3) , (7,5) , (8,6) , and (9,2)
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TheSmartOne (thesmartone):
And up all the x values which are in the form (x,y)
TheSmartOne (thesmartone):
Add***
OpenStudy (anonymous):
ohhh ok now I get 5.375
TheSmartOne (thesmartone):
Yes!
OpenStudy (anonymous):
thxs so if I round to the oneth place (5.375) it will be 5.4
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TheSmartOne (thesmartone):
No problem. And yes.
TheSmartOne (thesmartone):
it would be the tenth place... fyi
TheSmartOne (thesmartone):
:P lol
OpenStudy (anonymous):
ok thxs I have other question can you help me