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Evaluate this equation if a=2
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equation
\[a^2+3a^-4-a^0 \]
the 3a is ^-4
2*2+(3a)^-4-a^0
4-1/81(a^-4)-1=3-1/81a^-4
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can you put that in equation mode i can't read it
\[3-\frac{ 1 }{ 81 }\left( a ^{-4} \right)\]
isn't 2^4=16
@DanJS
@jim_thompson5910
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3^-4=1/81
if i plug in 2 3(2)^-4
what are my steps?
ahh watlet m redo
you mean 3^-4 times 2^-4?
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2*2+(3*2)^-4
multiply 3 by 2 first?
if 3a is in -4 poweer then yes
oo it's the same result
4-1/1296
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3 1/1296?
hmm no cant be
\[a ^{2}+(3a^{-4})\] is it correct?
there wasn't parenthesis but yes
k so (2^2)+(3*(2^-4))
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4+3*1/16
67/16
4 3/16
you mean 3+3/16
-2^0=-1
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4+3/16
it's 3
there is no 4
a=2 2^2=4
but let me ask you if it was (3 times 2)^-4 that would be 1/1256 right?
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yes
alright good looks
o
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