Question

Water is poured into an inverted cone. If the depth of the water is 2/3 of the height of the cone, what fraction of the lateral surface is wet? @ganeshie8

Answer 1

what do yuo think the answer is?

Answer 2

I don't know that's y im asking

Answer 3

Hint : if lengths are in ratio m/n, then areas will be in ratio (m/n)^2

Answer 4

that's right

Answer 5

since the depths are in ratio 2/3, the lateral areas will be in what ratio ?

Answer 6

4/9?

Answer 7

@ganeshie8

Answer 8

thats it!

Answer 9

thank u

Answer 10

yw