Question

The question is:
If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.
My code is:
int x = 1;
int y = 0;
while (x > 1000) {
if (x%3==0){
y = y+x;
}
++x;
}
cout << y;
but it doesn't work.

Answer 1

#include <iostream>
using namespace std;

int main() {
int x=1,sum=0;
while(x<10)
{
if(x%3==0||x%5==0)//Multiples of 3 and 5
{
sum=sum+x;//sum of the multiples
}
x++;
}
cout<<sum;//Displaying the Result
return 0;
}

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