Question

Help will give medal and fan

Answer 1

Anyone care to tell me what this is?

Answer 2

∀x Player(x) ^ (∃y,z Premium(y) ^ Buys(x, y, z)) => Awesome(x)

Answer 3

@ganeshie8

Answer 4

@perl

Answer 5

logic

Answer 6

logic?

Answer 7

you can translate it into english. but i'm not sure what the question is

Answer 8

how? can you teach me

Answer 9

i have to translate

Answer 10

it's a riddle gor a game :P

Answer 11

for*

Answer 12

is there a website you can link to me so i can read up on it

Answer 13

or the name of this subject

Answer 14

ok?

Answer 15

Let V = upside down A
E = backwards E

Vx Player(x) ^ (E(y,z) Premium(y) ^ Buys(x, y, z)) => Awesome(x)


For all x , if x is a player and there exists y,z such that y is a premium and x buys y for z , then x is awesome.

Or more simply

Any player that buys a premium for someone else is awesome.

Answer 16

okay i'll try that

Answer 17

it's wrong :(

Answer 18

Any player that buys a premium for someone is awesome

Answer 19

that's wrong?

Answer 20

yes

Answer 21

what are the choices given

Answer 22

there are none

Answer 23

wait someone just told me the answer

Answer 24

so how do you know its wrong?

Answer 25

Every player who buys premium is awesome

Answer 26

that is the answer apprently

Answer 27

yup it's right

Answer 28

the statement says more than that,
every player who buys premium for someone (which could include himself) is awesome

Answer 29

but simply , yes. every player who buys premium is awesome. maybe i'm wrong :)

Answer 30

still i thank you for the help you supplied :)

Answer 31

may i ask where you got this question?

Answer 32

This would make more sense, if we get rid of the z.

Vx Player(x) ^ (E(y) Premium(y) ^ Buys(x, y) => Awesome(x)

For all x , if x is a player and there exists y such that y is a premium and x buys y , then x is awesome.

Or more simplfy
Every player who buys a premium is awesome. ;)