Question

What is the nth term of the geometric sequence that has a common ratio of 6 and 24 as its third term?

Answer 1

a term in a geometric series is

\[a_{n} = a_{1} r^{n - 1}\]

so you need to find the 1st term, knowing r = 6 and n = 3 and the 3rd term = 24

\[24 = a \times 6^{n - 1}\]

solve for a, then substitute your value for a and r into the general form