Mathematics
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OpenStudy (anonymous):
Find the x-intercepts (if any) for the graph of the quadratic function.
6x2 + 12x + 5 = 0
Give your answers in exact form. Show your work.
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hartnn (hartnn):
to get x intercepts
plug in y=0
hartnn (hartnn):
ok, you don't have a y there
just solve that quadratic :P
OpenStudy (anonymous):
i did i check it
OpenStudy (anonymous):
hartnn (hartnn):
sure
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OpenStudy (anonymous):
she ask me exact form i dontknow why its not coming maybe my calculator error plzz re-d and check
hartnn (hartnn):
it has x intercepts
OpenStudy (anonymous):
check my attacthment
hartnn (hartnn):
\((-12\times 5)\)
^^ incorrect
hartnn (hartnn):
shouldn't it just be
12*5
?
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OpenStudy (anonymous):
@master50777 u here?
OpenStudy (anonymous):
oh yes @hartnn
next error?
hartnn (hartnn):
no other error :)
answer will change
OpenStudy (anonymous):
but formal had negative sign already
hartnn (hartnn):
\(b^2-4ac \\ 12^2 -4(12)(5)\)
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OpenStudy (anonymous):
144-56
OpenStudy (anonymous):
Sqrt 88
hartnn (hartnn):
sorry
\(12^2-4\times 6\times 5\)
hartnn (hartnn):
144-120 = 24
\(\sqrt {24}\)
OpenStudy (anonymous):
final answer 0.41
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OpenStudy (anonymous):
@hartnn
hartnn (hartnn):
ok,
\(\dfrac{-12 \pm \sqrt{24}}{12} = \dfrac{-3\pm \sqrt 6}{3}\)
OpenStudy (anonymous):
hartnn (hartnn):
yeah, correct :)
OpenStudy (anonymous):
thnaks :)
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OpenStudy (anonymous):
ill be doing my other test which is complete but has some error and i need to review could u help me in those Q's
hartnn (hartnn):
sure :)
just ask each question in a new post :)
OpenStudy (anonymous):
ok :)