Question

I'm not sure if I got this right -> Present the following into an algerbriac expression: A number doubles every time another number increases by one. Let x be the first number and y the second. What's the value of x if y increases by 16, assuming x = 2 and y = 1 wherein x = 2y?

Answer 1

I got the following:
\[x = 2(y+n)\]\[x = 2(1+16) = 2(17) = 34\]

Answer 2

thats correct! :)

Answer 3

thanks :)

Answer 4

no prb