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In the figure, the sides of triangle ABC are produced so AB=BP, BC=CQ, CA=AR. FInd the ratio of the area of PQR to ABC
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The area of a triangle is (1/2)*base*height If triangle 1 is some constant times triangle 2 T1 = k*T2 Then the Areas will relate by the square of the constant
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Area T1 = (1/2)*b*h Area T2 = (1/2)*(k*b)*(k*h) = k^2 *(1/2)b*h
T2 = k^2 *T1
the ratio of the areas, will be the square of that linear ratio
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Is that diagram in Euclid's Elements somewhere?
i d k
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