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Am I doing this correctly? QUESTION: Complete the square in the quadratic function f given by f(x) = 2x2 - 6x + 4? ANSWER: f(x) = 2(x2 - 3x) + 4 : factor 2 out in the first two terms = 2(x2 - 3x + (-3/2)2 - (-3/2)2) + 4 : add and subtract (-3/2)2 = 2(x - 3/2))2 + 17/2 : complete square and group like terms.
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looks good to me
you did it right
x squared -- x^2
Thank you so much
the second line has some error..... {2(x2 - 3x + (-3/2)2 - (-3/2)2) + 4} -3x..... it should come from 2*a*b.....so a=x, you need b=?.
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2ab=-3x 2xb=-3x b=-3/2
2(x^2-3/2x+(-3/2)^2-(-3/2)^2)+4 2(x^2-3/2x+9/4-9/4)+4 2(x^2-3/2x+9/4)-2*9/4+4 2(x-3/2)^2-18/4+4*(4/4) 2(x-3/2)^2+(-18+16)/4 2(x-3/2)^2-1/2
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