A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is:
A. 35
B. 36
C. 37
D. 40

Question

A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is:
A.	35	
B. 36
C.	37
D.	40

anonymous · Answer

change words to equations:
s=(v+3)*(t-40).--->1
s = (v-2)*(40+t).--->2
s=v*t.---->3
then expand them out and get 
1-2 .
and 2-3.
thus 1-2 = 2-3.

shaik0124 · Answer

thank u

anonymous · Answer

noo i forget to convert them to hours
t+2/3
t-2/3

anonymous · Answer

you will get from 1-2
v=(15/4)t-0.5
and from 1-3
v=3t+2.
thus t = 10/3 and v = 12.
so s = 40 km.

shaik0124 · Answer

t+2/3 ??

anonymous · Answer

yea 
$$1 hr = 60 \min$$
1 ---> 60
x ___> 40
thus x = 40/60 =2/3 hr.