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@DanJS
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i like how you close it out, so the trolls on the site dont interrupt to show how much they know, like anyone really cares
hahahha yes you understand!!
so i just did this problem and got 4.5 but im redoing it because it doesnt look right
k 1 sec
so the slope of that f ' (x) is the acceleration , which is a constant -1
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from -3 to 0
Let over the inverval [-3,0] f ' '(x) = -1 f '(x) = -1x f (x) = -(1/2) x^2 + C when x=0 y=7 so f(x) = (-1/2) x^2 + 7
oh wait now i got 4.5
I got 2.5 is the minimum value for f at x=-3
see how i came up with those equations?
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yess
thanks(:
i only have one more question if you could help me (:
sure
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