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@ganeshie8 one more please?
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\(\sf\dfrac{sinx}{1-cosx}+\dfrac{sinx}{1+cosx}=2cscx\)
can I help??
simplify the left side by combining the fractions
take sinx common
\(\sf\dfrac{2sinx}{2}=2cscx\)?
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solve \[1/1-\cos x+1/1+cosx\]
how did you get a 2 on the bottom?
sinx comes in denominator
small mistake @sleepyjess
Welp, looks like you've asked the same question again.
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on solving u will get 2/sin^2x
1+1 in the denominators
(1-cosx)(1+cosx)=1-cos^2x
\[finally~u~have~ 2sinx/\sin^2x\]
so sinx comes in the denominator.......
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which gives us the RHS
1+1 in the Nr
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