Question

HELP PLEASE

Answer 1

@iGreen
@SolomonZelman
@TheSmartOne

Answer 2

ohh wait is the negative real roots 3,1

Answer 3

GUYS DO YOU NOT KNOW DECARTES RULE OF SIGHNS

Answer 4

yes

Answer 5

At least your honest

Answer 6

What is it you don't understand? If you click on the button I haven't learned this yet it will show you correct?

Answer 7

no it will just move on and i will loose points

Answer 8

Here is a good site if you don't understand the rules. Note, it will only tell you how many roots there are and not give you the roots.

http://www.purplemath.com/modules/drofsign.htm

If you just want to know how many roots there are you can just put that equation into this site and it will tell you.

http://www.wolframalpha.com/

Answer 9

@mathgirl2012

There is only 1 sign change in Q(x) so your possible number of positive real roots is correct.

Please re-think the number of negative real root possibilities.

Answer 10

3,1 negative

Answer 11

Replace the x in Q(x) by (-x) and crank out Q(-x).

Then, count the sign changes. The number of negative real root possibilites = the number of sign changes or less that by 2.

Answer 12

>3,1 negative This is what I got, too.

Answer 13

Here is the link that shows you the roots from Wolfram

http://www.wolframalpha.com/input/?i=roots+of+Q%28x%29+%3D+-8x%5E4+%2B+-8x%5E3+-+3x%5E2+-+2x+%2B+4
It might be useful in the future.

Answer 14

can you guys help me on my next problem open algebra and it is the first one