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How sinθ=sin(180-θ)? (According to this attached image).
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(I don't understand how you can do sin(180-theta). Theta is obtuse. Sin is only for right angle, no?
sin (A-B)=sin(A)cos(B)-sin(B)cos(A) A=180 sin(180)=0 cos(180)=-1 sin(A-B)=0-(sin(B)*(-1))=sin(B)
I know this identity, I just ask about seeing it from the unit circle :(
find co-ordinates of P and P'
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y co-ordinate of P gives sin theta y co-ordinate of P' gives sin (180-theta)
check whether they are equal :)
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