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OpenStudy (anonymous):
find the circumference of the circle whose area is 16times the area of the cirlce with diameter 1.4cm
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OpenStudy (anonymous):
@Jhannybean
OpenStudy (anonymous):
@mathmath333
OpenStudy (mathmath333):
\(\large\tt \begin{align} \color{black}{
A_c=16A_1
}\end{align}\)
u agree
OpenStudy (anonymous):
yes
OpenStudy (mathmath333):
\(\large\tt \begin{align} \color{black}{
A_c=16A_1\\~\\
\pi (r_c)^2=16\pi (r_1)^2\\~\\
}\end{align}\)
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OpenStudy (mathmath333):
is that ok
OpenStudy (anonymous):
yes
OpenStudy (mathmath333):
\(\large\tt \begin{align} \color{black}{
(r_c)^2=16( r_1)^2\\~\\
r_c=4r_1
}\end{align}\)
ok
OpenStudy (anonymous):
yes
OpenStudy (mathmath333):
\(\large\tt \begin{align} \color{black}{
r_c=4r_1\\~\\
r_c=2(2r_1)\\~\\
r_c=2(d_1)\\~\\
r_c=2(1.4)\\~\\
}\end{align}\)
is thatok
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OpenStudy (anonymous):
yes
OpenStudy (mathmath333):
\(\large\tt \begin{align} \color{black}{
r_c=2(1.4)\\~\\
r_c=2.8\\~\\
2\pi r_c=2\pi\times 2.8\\~\\
C=2\pi \times 2.8\\~\\
}\end{align}\)
OpenStudy (anonymous):
is it 22 x 0.8?
OpenStudy (mathmath333):
\(C=2\times \dfrac{22}{7}\times 2.8\\~\\\)
OpenStudy (anonymous):
i did that i got 44 x 0.8??
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