Question

Verify the identity.
\(\sf cot(x-\dfrac{\pi}{2})=-tan~x\)

Answer 1

@thomaster

Answer 2

@Directrix

Answer 3

use this identities


\(\large\tt \begin{align} \color{black}{
\cot x=\dfrac{1}{\tan x}
\\~\\
\tan (A+B)=\dfrac{\tan A+\tan B}{1-\tan A\tan B}
}\end{align}\)

Answer 4

I think you need to apply this formula. Maybe @mathmath333 will post it so we can see it better.

Answer 5

This identity should fall right out with that.

Answer 6

Like this? \(\sf cot(a-b)=\dfrac{1+tan~a~tan~b}{tan~a-tan~b}\)

Answer 7

Yes. Thanks. I'll draw (I'm low tech) how to begin.