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Find all solutions to the equation in the interval [0,2pi). 2cos^2x+cosx-1=0. Thanks!
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this is a quadratic equation can you factor it?
Then It factors So or Hence or So or Find these values on the unit circle: bearing in mind that the cosine is represented by the -coordinate of a point on the unit circle and don't miss the fact that your given interval is inclusive of BOTH end points.
please, try this substitution: \[\cos x=y\]
Refer to the solution process from WolframAlpha.
please substitute y in place of cos x, keep in mind that: \[(\cos x)^{2}=y ^{2}\]
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