SOLVE FOR Y: x = 7y x + y + z = 80 2x - y + z = 105 A. -7 B. 15 C. -175/13 D. 35 E. none of these
ok
This one i think is D? i know you have to solve by substitution.
Take the first equation x = 7y, and replace x in the second equation with that
7y + y + z = 80 2(7y) - y + z = 105 I replaced X in the second 2 equations with x= 7y, good with that so far?
yes.
now you have 2 equations with 2 unknowns Y and Z,, we can solve this by a couple methods
adding the Y's to simplify a little bit 8Y + Z = 80 13Y + Z = 105
we can multiply one of the equations by a constant number and then add them together,
here, if you multiply one of them by -1, then when you add them you get +Z-Z = 0 the Z will go to zero
(-1)(8Y + Z = 80 ) multiply first by -1 13Y + Z = 105 ------------------- -8Y - Z = -80 13Y + Z = 105 ADD the two together -------------- 5Y + 0Z = 25 no Z's Left now 5Y = 25 divide by 5 both sides Y = 5
Do you recall doing this kind of thing in class?
okay that's what i was getting as well, i got 35 for x 5 for y and 40 for z when i did it.
yes we did this in class.
ok, just want to make sure i am using a similar method to what you are learning...
Now that you figured Y=5, you can use that in the first equation to get X X = 7Y = 7*5 = 35 X=35
Now you know X and Y, use any of the last 2 equations to get Z
which would come to z = 40, right?
Using equation 2, x + y + z = 80 and X=5 , Y = 35 5 + 35 + z = 80 z = 40 yep
alright :) i'm glad i'm doing this correctly then. so the right answer would be E for this then. you're the best!! would you mind helping me with the other one as well?
If you wanted to check after you finished, use x=5 y=35 z=40 plug those into all 3 equations and see if they all are true
oh, Y=5, X=35, Z=40. typo above
okay! thank you. im glad that i know this method correctly.
Right , answer is NONE, Y=5
cool, welcome, anytime
Join our real-time social learning platform and learn together with your friends!