Question

show that in \(R\) set the \(\bar Q\) (closure of Q (rational numbers )) is the same as \(R\).

Answer 1

@eliassaab @zzr0ck3r

Answer 2

its the same as show Q is dense , do u remember it from real analysis ?

Answer 3

@ganeshie8

Answer 4

You want to show an open ball consisting of rational numbers exists around each real number

Answer 5

i wanna find closure for Q , means the smallest closed set that contains Q
note that R is close and open