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Algebra
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solve using factoring: x^2-3x-18
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(x + 3) • (x - 6)
(x+3)(x-6)
To do this problem x^2-3x-18 we can ask our self two numbers that are the product of -18, meaning what times what equals 18 and ask our self if the two numbers are the sum of -3, which is the middle number. So 3 times -6 = -18 and 3 + (-6) = -3 This means 3 and -6 will work. Now just split the x^2. So we get (x+3)(x-6)
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